Integrand size = 28, antiderivative size = 221 \[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(b d+2 c d x)^{13/2}} \, dx=-\frac {3 \sqrt {a+b x+c x^2}}{154 c^2 d^3 (b d+2 c d x)^{7/2}}+\frac {\sqrt {a+b x+c x^2}}{77 c^2 \left (b^2-4 a c\right ) d^5 (b d+2 c d x)^{3/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{11 c d (b d+2 c d x)^{11/2}}+\frac {\sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {b d+2 c d x}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right ),-1\right )}{154 c^3 \left (b^2-4 a c\right )^{3/4} d^{13/2} \sqrt {a+b x+c x^2}} \]
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Time = 0.12 (sec) , antiderivative size = 221, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {698, 707, 705, 703, 227} \[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(b d+2 c d x)^{13/2}} \, dx=\frac {\sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {b d+2 c x d}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right ),-1\right )}{154 c^3 d^{13/2} \left (b^2-4 a c\right )^{3/4} \sqrt {a+b x+c x^2}}+\frac {\sqrt {a+b x+c x^2}}{77 c^2 d^5 \left (b^2-4 a c\right ) (b d+2 c d x)^{3/2}}-\frac {3 \sqrt {a+b x+c x^2}}{154 c^2 d^3 (b d+2 c d x)^{7/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{11 c d (b d+2 c d x)^{11/2}} \]
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Rule 227
Rule 698
Rule 703
Rule 705
Rule 707
Rubi steps \begin{align*} \text {integral}& = -\frac {\left (a+b x+c x^2\right )^{3/2}}{11 c d (b d+2 c d x)^{11/2}}+\frac {3 \int \frac {\sqrt {a+b x+c x^2}}{(b d+2 c d x)^{9/2}} \, dx}{22 c d^2} \\ & = -\frac {3 \sqrt {a+b x+c x^2}}{154 c^2 d^3 (b d+2 c d x)^{7/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{11 c d (b d+2 c d x)^{11/2}}+\frac {3 \int \frac {1}{(b d+2 c d x)^{5/2} \sqrt {a+b x+c x^2}} \, dx}{308 c^2 d^4} \\ & = -\frac {3 \sqrt {a+b x+c x^2}}{154 c^2 d^3 (b d+2 c d x)^{7/2}}+\frac {\sqrt {a+b x+c x^2}}{77 c^2 \left (b^2-4 a c\right ) d^5 (b d+2 c d x)^{3/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{11 c d (b d+2 c d x)^{11/2}}+\frac {\int \frac {1}{\sqrt {b d+2 c d x} \sqrt {a+b x+c x^2}} \, dx}{308 c^2 \left (b^2-4 a c\right ) d^6} \\ & = -\frac {3 \sqrt {a+b x+c x^2}}{154 c^2 d^3 (b d+2 c d x)^{7/2}}+\frac {\sqrt {a+b x+c x^2}}{77 c^2 \left (b^2-4 a c\right ) d^5 (b d+2 c d x)^{3/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{11 c d (b d+2 c d x)^{11/2}}+\frac {\sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \int \frac {1}{\sqrt {b d+2 c d x} \sqrt {-\frac {a c}{b^2-4 a c}-\frac {b c x}{b^2-4 a c}-\frac {c^2 x^2}{b^2-4 a c}}} \, dx}{308 c^2 \left (b^2-4 a c\right ) d^6 \sqrt {a+b x+c x^2}} \\ & = -\frac {3 \sqrt {a+b x+c x^2}}{154 c^2 d^3 (b d+2 c d x)^{7/2}}+\frac {\sqrt {a+b x+c x^2}}{77 c^2 \left (b^2-4 a c\right ) d^5 (b d+2 c d x)^{3/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{11 c d (b d+2 c d x)^{11/2}}+\frac {\sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \text {Subst}\left (\int \frac {1}{\sqrt {1-\frac {x^4}{\left (b^2-4 a c\right ) d^2}}} \, dx,x,\sqrt {b d+2 c d x}\right )}{154 c^3 \left (b^2-4 a c\right ) d^7 \sqrt {a+b x+c x^2}} \\ & = -\frac {3 \sqrt {a+b x+c x^2}}{154 c^2 d^3 (b d+2 c d x)^{7/2}}+\frac {\sqrt {a+b x+c x^2}}{77 c^2 \left (b^2-4 a c\right ) d^5 (b d+2 c d x)^{3/2}}-\frac {\left (a+b x+c x^2\right )^{3/2}}{11 c d (b d+2 c d x)^{11/2}}+\frac {\sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt {b d+2 c d x}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right )\right |-1\right )}{154 c^3 \left (b^2-4 a c\right )^{3/4} d^{13/2} \sqrt {a+b x+c x^2}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.06 (sec) , antiderivative size = 107, normalized size of antiderivative = 0.48 \[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(b d+2 c d x)^{13/2}} \, dx=\frac {\left (b^2-4 a c\right ) \sqrt {d (b+2 c x)} \sqrt {a+x (b+c x)} \operatorname {Hypergeometric2F1}\left (-\frac {11}{4},-\frac {3}{2},-\frac {7}{4},\frac {(b+2 c x)^2}{b^2-4 a c}\right )}{88 c^2 d^7 (b+2 c x)^6 \sqrt {\frac {c (a+x (b+c x))}{-b^2+4 a c}}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(610\) vs. \(2(187)=374\).
Time = 4.69 (sec) , antiderivative size = 611, normalized size of antiderivative = 2.76
method | result | size |
elliptic | \(\frac {\sqrt {d \left (2 c x +b \right ) \left (c \,x^{2}+b x +a \right )}\, \left (-\frac {\left (4 a c -b^{2}\right ) \sqrt {2 c^{2} d \,x^{3}+3 b c d \,x^{2}+2 a d x c +b^{2} d x +a b d}}{2816 c^{8} d^{7} \left (x +\frac {b}{2 c}\right )^{6}}-\frac {13 \sqrt {2 c^{2} d \,x^{3}+3 b c d \,x^{2}+2 a d x c +b^{2} d x +a b d}}{4928 c^{6} d^{7} \left (x +\frac {b}{2 c}\right )^{4}}-\frac {\sqrt {2 c^{2} d \,x^{3}+3 b c d \,x^{2}+2 a d x c +b^{2} d x +a b d}}{308 c^{4} \left (4 a c -b^{2}\right ) d^{7} \left (x +\frac {b}{2 c}\right )^{2}}-\frac {\left (\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}+\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}\right ) \sqrt {\frac {x +\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}}{\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}+\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}}}\, \sqrt {\frac {x +\frac {b}{2 c}}{-\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}+\frac {b}{2 c}}}\, \sqrt {\frac {x -\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}}{-\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}-\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}}}\, F\left (\sqrt {\frac {x +\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}}{\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}+\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}}}, \sqrt {\frac {-\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}-\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}}{-\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}+\frac {b}{2 c}}}\right )}{154 c^{2} \left (4 a c -b^{2}\right ) d^{6} \sqrt {2 c^{2} d \,x^{3}+3 b c d \,x^{2}+2 a d x c +b^{2} d x +a b d}}\right )}{\sqrt {d \left (2 c x +b \right )}\, \sqrt {c \,x^{2}+b x +a}}\) | \(611\) |
default | \(\text {Expression too large to display}\) | \(1046\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.12 (sec) , antiderivative size = 374, normalized size of antiderivative = 1.69 \[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(b d+2 c d x)^{13/2}} \, dx=\frac {\sqrt {2} {\left (64 \, c^{6} x^{6} + 192 \, b c^{5} x^{5} + 240 \, b^{2} c^{4} x^{4} + 160 \, b^{3} c^{3} x^{3} + 60 \, b^{4} c^{2} x^{2} + 12 \, b^{5} c x + b^{6}\right )} \sqrt {c^{2} d} {\rm weierstrassPInverse}\left (\frac {b^{2} - 4 \, a c}{c^{2}}, 0, \frac {2 \, c x + b}{2 \, c}\right ) + 2 \, {\left (32 \, c^{6} x^{4} + 64 \, b c^{5} x^{3} - b^{4} c^{2} - 2 \, a b^{2} c^{3} + 56 \, a^{2} c^{4} + 2 \, {\left (11 \, b^{2} c^{4} + 52 \, a c^{5}\right )} x^{2} - 2 \, {\left (5 \, b^{3} c^{3} - 52 \, a b c^{4}\right )} x\right )} \sqrt {2 \, c d x + b d} \sqrt {c x^{2} + b x + a}}{308 \, {\left (64 \, {\left (b^{2} c^{10} - 4 \, a c^{11}\right )} d^{7} x^{6} + 192 \, {\left (b^{3} c^{9} - 4 \, a b c^{10}\right )} d^{7} x^{5} + 240 \, {\left (b^{4} c^{8} - 4 \, a b^{2} c^{9}\right )} d^{7} x^{4} + 160 \, {\left (b^{5} c^{7} - 4 \, a b^{3} c^{8}\right )} d^{7} x^{3} + 60 \, {\left (b^{6} c^{6} - 4 \, a b^{4} c^{7}\right )} d^{7} x^{2} + 12 \, {\left (b^{7} c^{5} - 4 \, a b^{5} c^{6}\right )} d^{7} x + {\left (b^{8} c^{4} - 4 \, a b^{6} c^{5}\right )} d^{7}\right )}} \]
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Timed out. \[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(b d+2 c d x)^{13/2}} \, dx=\text {Timed out} \]
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\[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(b d+2 c d x)^{13/2}} \, dx=\int { \frac {{\left (c x^{2} + b x + a\right )}^{\frac {3}{2}}}{{\left (2 \, c d x + b d\right )}^{\frac {13}{2}}} \,d x } \]
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\[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(b d+2 c d x)^{13/2}} \, dx=\int { \frac {{\left (c x^{2} + b x + a\right )}^{\frac {3}{2}}}{{\left (2 \, c d x + b d\right )}^{\frac {13}{2}}} \,d x } \]
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Timed out. \[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(b d+2 c d x)^{13/2}} \, dx=\int \frac {{\left (c\,x^2+b\,x+a\right )}^{3/2}}{{\left (b\,d+2\,c\,d\,x\right )}^{13/2}} \,d x \]
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